Data Sufficiency Question 32

Directions : Each of the questions given below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements sufficient to answer the question. Read both the statements and

(IDBI Officer Grade Exam. 22.08.2014)

Give answer (1) if the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question. Give answer (2) if the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question.

Give answer (3) if the data in statement I alone or in statement II alone are sufficient to answer the question.

Give answer (4) if the data in both the statements I and II are not sufficient to answer the question.

Give answer (5) if the data in both the statements I and II together are necessary to answer the question.

  1. What is the monthly salary of Manish?

I. Manish spends $18 %$ of his salary on grocery and $14 %$ of it on academic activities. $14 %$ of total salary is spent on transportation and entertainment. $\frac{3}{10}$ th part of the total salary is spent on house rent and thereafter he saves ₹ 32000.

II. The salary of Manish increased by $33 \frac{1}{3} %$ two years ago and $25 %$ a year ago. The difference in increase was ₹ $\frac{32000}{3}$.

Show Answer

Correct Answer: 32. (3)

Solution: 32. (3) From statement I,

Total expenditure of Manish

$=\frac{18+14+13}{100}+\frac{3}{10}$

$=\frac{45}{100}+\frac{3}{10}$

$=\frac{9}{20}+\frac{3}{10}$

$=\frac{9+6}{20}=\frac{15}{20}=\frac{3}{4}$ part

Remaining part $=1-\frac{3}{4}=\frac{1}{4}$

$\therefore$ Total salary $=4 \times 32000$

= ₹ 128000

From statement II,

If the monthly salary be $₹ x$, then

$x \times\left(\frac{100}{3}-25\right) %$

$ \begin{aligned} & =\frac{32000}{3} \\ & \Rightarrow x \times \frac{25}{300}=\frac{32000}{3} \\ & \Rightarrow x=\frac{32000 \times 300}{25 \times 3} \\ & =₹ 128000 \end{aligned} $