Data Interpretation Ques 80
Directions : Study the following table carefully to answer the questions that follow :
Number of Passengers (in hundreds) travelling in five trains on six different days
| Train | A | B | C | D | E |
|---|---|---|---|---|---|
| Day | |||||
| Monday | 4.55 | 4.38 | 4.64 | 7.73 | 7.68 |
| Tuesday | 3.54 | 6.34 | 6.90 | 5.82 | 5.59 |
| Wednesday | 7.65 | 2.79 | 7.23 | 5.64 | 6.28 |
| Thursday | 6.75 | 8.65 | 7.83 | 9.74 | 8.83 |
| Friday | 5.78 | 9.50 | 8.91 | 8.16 | 6.54 |
| Saturday | 3.48 | 5.39 | 9.84 | 9.92 | 10.9 |
If four-eleventh of the number of passengers in Train-C on Friday is travelling without ticket, then what is the number of passengers having tickets?
(1) 567
(2) 546
(3) 576
(4) 564
(5) None of these
Show Answer
Correct Answer: (1)
Solution: (1) Required number of travellers with ticket
$$ \begin{aligned} & =8.91 \times\left(1-\frac{4}{11}\right) \times 100 \\ & =8.91 \times \frac{7}{11} \times 100=567 \end{aligned} $$
BETA
