Data Interpretation Ques 101
Directions : Study the following table carefully to answer the questions that follow:
Amount earned (in lacs) by five
persons in six different years| Person | | | | | | | | | | :— | :—: | :—: | :—: | :—: | :—: | :—: | :—: | :—: | | Year | A | B | C | D | E | | | | | 2005 | 2.24 | 4.33 | 5.64 | 3.73 | 1.69 | | | | | 2006 | 1.44 | 3.34 | 6.93 | 5.52 | 5.52 | | | | | 2007 | 4.63 | 2.79 | 7.52 | 5.68 | 4.28 | | | | | 2008 | 6.65 | 6.63 | 5.83 | 6.74 | 6.83 | | | | | 2009 | 5.34 | 4.50 | 5.94 | 8.42 | 5.53 | | | | | 2010 | 7.38 | 5.36 | 7.84 | 9.45 | 9.94 | | | |
Total amount earned by PersonA in the year 2006 and Person-C in the year 2010 together was approximately what percent of the amount earned by Person- $E$ in the year 2009 ?
(1) $151 \%$
(2) $155 \%$
(3) $168 \%$
(4) $174 \%$
(5) $162 \%$
Show Answer
Correct Answer: (3)
Solution: (3) Required percentage
$$ \begin{aligned} & =\frac{(1.44+7.84)}{5.53} \times 100 \\ & =\frac{9.28 \times 100}{5.53} \times 100 \approx 168 \% \end{aligned} $$
BETA
