Alligation Or Mixture Ques 17
Question
Vessel A contains $x$ litre milk and vessel B contains $y$ litre water. From vessels A and B, $60 \%$ milk and $12 \%$ water were taken and mixed in vessel $C$. The respective ratio between quantities of milk and water in vessel $C$ was $25: 4$. If $x$ was 20 litre more than $y$, what is the quantity of milk in vessel C? (in litre)
(1) 60
(2) 80
(3) 90
(4) 50
(5) 75
(IBPS SO (IT Officer) CWE (Prelim Exam) 30.12.2017)
Show Answer
Answer: (1)
Solution: (1)
According to the question, $x=y+20 \ldots$. (i)
Again,
$\frac{\frac{60x}{100}}{\frac {12y}{100}}$ $=\frac{25}{4}$
$\Rightarrow \frac{60 x}{12 y}=\frac{5 x}{y}=\frac{25}{4}$
$\Rightarrow \frac{x}{y}=\frac{5}{4} $
$\Rightarrow \frac{x}{x-20}=\frac{5}{4}$
$\Rightarrow 5 x-100=4 x$
$\Rightarrow 5 x-4 x=100 $
$\Rightarrow x=100$
$\therefore$ Quantity of milk in vessel $C=$ 60 litres.
BETA
