Alligation Or Mixture Ques 10
Question
There are two containers $A$ and B containing $40 \%$ milk. The quantity in $B$ is three times of the quantity in $A$. The quantities of both $A$ and $B$ are mixed into a third container $C$ and 10 litres of water is added to it. The ratio of milk to water in the resulting mixture is $4: 11$. The initial quantity (in litres) in $A$ is
(1) 4
(2) 5
(3) 6
(4) 8
(5) None of these
(IBPS Bank PO/MT CWE (Main))
Show Answer
Answer: (2)
Solution: (2)
Let the initial quantity in $A$ be $x$ litres.
$\therefore$ Initial quantity in C $=x+3 x=4 x$
Since the concentration of milk in both $A$ and $B$ is $40 \%$ the milk Concentration of initial mixture in C will also be $40 \%$
Milk content in $C=\frac{40}{100} \times 4 x=$ $1.6 x$
Inital water content in $C$ $=4 x-1.6 x=2.4 x$
Final water content in C $=2.4 x+10$
From question,
$\frac{1.6 x}{2.4 x+10}=\frac{4}{11}$
$\frac{0.4 x}{2.4 x+10}$ $=\frac{1}{11}$
$\Rightarrow 4.4 x=2.4 x+10$
$\Rightarrow 2 x=10$
$x=5$ litres.
BETA
